Andrew Levitt & Prof.
Eric Weeks 
<weeks(at)physics.emory.edu>
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Quick answers:
85% cyclohexylbromide / 15% decalin
 Viscosity eta: 2.24941 mPa s (about 2.25 times larger than water)
 Density: 1.23397 g/cm^3
 Index of refraction: 1.495 (Scott Franklin, 5107)
Using measured values of solvent viscosity, particularly the 85% CXB
/ 15% DEC mixture, and information about the diffusion of particles in
that solvent, particle radii can be determined. This webpage contains
viscometry data (measured viscometer efflux times, solvent density
measurements) and equations relating diffusion time to particle radius.
Solvent viscosity is measured using a glass CannonFenske kinematic
viscometer. This device relates a liquid's viscosity to the time it
takes for the liquid to fall a given distance through a skinny tube.
This time is called the efflux time. By multiplying the efflux time by
the viscometer constant for the appropriate temperature and the solvent
density, one obtains the viscosity in millipascal seconds (centipoise).
These are the viscometer constants for our CannonFenske
viscometer no. 50 Y871: 
 .004407 mm^2/s^2 at 40 deg. Celsius
 .004385 mm^2/s^2 at 100 deg. Celsius.
 Extrapolation to 22 deg. gives a constant of .0044136.

The efflux times that I measured for the CXB/DEC mixture in question are:

 413.380 seconds
 414.740 seconds
 410.940 seconds
 avg = 413.020 s
stddev = 1.92540 s

These are my weight measurements for 25 mL of solvent measured into a
volumetric flask.

 30.8895 g
 30.8344 g
 30.8317 g
 30.8411 g
 avg=30.8492 g
stddev = .0271721 g

These return a density of:


Multiplying the viscometer constant by the efflux time returns
a kinematic viscosity nu of:

 1.82291 cSt = 0.0182291 cm^2/s
 (note: kinematic viscosity of water ~1 cSt = 0.01 cm^2/s)

Multiplying the viscometer constant by the efflux time and the density returns
a bulk viscosity eta of:

 2.24941 mPa s
 (milliPascal seconds)
 (note: bulk viscosity of water 1.002 mPa s at 20 deg C)

Einstein says:
dx^2(dt) = 2D*dt
where dx is onedimensional RMS particle displacement in some time dt.
D is:
KT/6(pi)va
where K is Boltmann's constant, T is temperature in Kelvin,
v is bulk viscosity as above,
and a is particle radius. Take a lot of data of diffusive motion of your particles,
in a dilute sample where the particles don't bump into each other much. There
should be ~100 particles per frame. The MSD will be linear; this is the
function listed in the first equation above. Find the slope of this graph; this
is equal to 2D. If you use data from x^2 + y^2, then the slope is equal
to 4D. Slope = 2KT/6(pi)va, a = 2KT/[6(pi)v*Slope]. Presto.
K is 1.381e23 in MKS
T = 295 in the lab
v = 2.25e3 in MKS
slope = slope of MSD in microns^2 per second times 10^12 to get MKS
The result should be something like 1.1e6 (a is the radius,
not diameter). We've used this webpage for many years, so if you
don't get this result, you probably made a mistake.